Solving Circuit with Large Resistor and Inductor: Q = CV?

[bodensee9]

Homework Statement

Hello:

I've this circuit:
-----Resistor (100000 ohms)---/ (switch) -------
| | |A
Battery Capacitor Inductor
| | |
| | Resistor2
|_________________________|______________|B
At points A, B, they are connected to a oscilloscope. The inductor/resistor2 combination have an inductance of 0.01 henry. When the switch is closed, the oscillatorscope is triggered.

I think that you'd have 2 currents, I1 and I2, if I1 flows clockwise through the large resistor and then I2 flows counterclockwise through the second loop of the circuit. I think you can isolate the loop of I2 since resistance in the first loop resistor is so large (100000 ohms). So then I can just do C is approximately 1/w^2L, where L is the inductance and w is the angular frequency (which I am supposed to determine on a separate chart). But I am asked how I am supposed to find an expression for the charge on the capacitor? I know that Q = CV. So then V across this LResistor2 combination is the same as voltage across C.

Homework Equations

Q = CV
I = dQ/dt
V = LdI/dt + RI

The Attempt at a Solution

do I have:
$$V = \frac{dI_{2}}{dt} + R_{2}I_{2}$$, which is
$$Q/C=\frac{d^{2}Q}{dt^{2}} + R_{2}\frac{dQ}{dt}$$
and then
$$V = R_{1}I_{1} + Q/C$$?
Actually, not sure what to do about the rest? Thanks.

 

[kuruman]

Your circuit diagram did not come through in any way that can be interpreted. Also, it is not clear what you are asked to find.

 

[bodensee9]

Oh sorry, but never mind. I will just use old Kirchoff's Laws and write down the expression fot voltage across the 2 loops, and then derive the answer that way. Thanks anyway.