Solving Combinations Problem with up to 5 Roles: 40 Employees

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SUMMARY

The problem of selecting a union of 5 people from 40 employees, where each person can hold multiple roles, is solved using the formula for combinations with replacement. Specifically, since each of the 5 positions can be filled by any of the 40 employees, the total number of combinations is calculated as 40 raised to the power of 5, represented mathematically as 405. This approach accounts for the possibility of selecting the same employee for multiple roles.

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Yankel
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Hello,

How do I solve this problem:

In a factory there are 40 employees. A union of 5 people is being chosen.
How many combinations are they, if the union of 5 people contains 5 different roles, and an employee can have more than one role (up to 5) ?

It is like sampling with replacement, so it isn't just:

{40 \choose 5}Thanks...
 
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Yankel said:
Hello,

How do I solve this problem:

In a factory there are 40 employees. A union of 5 people is being chosen.
How many combinations are they, if the union of 5 people contains 5 different roles, and an employee can have more than one role (up to 5) ?

It is like sampling with replacement, so it isn't just:

{40 \choose 5}Thanks...

It is not ${40 \choose 5}$..

There are $5$ positions and $40$ employees.

For the first position, there are $40$ possible employees.
For the second position, there are again $40$ possible employees, since the one that is chosen for the first position can also be chosen for the second position.
For the third position, there are again $40$ possible employees, for the same reason.
For the $4^{th}$ position, there are $40$ possible employees.
Fot the $5^{th}$ position, there are $40$ possible employees.

So, there are $\displaystyle{40^5}$ possible ways to create the union.
 

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