Solving Concentration Problems: Sodium Cations

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Homework Statement


15 cm3 of 0.200 mol dm-3 sodium hydroxide solution was made up to 100 cm3 with 0.120 mol dm-3 sodium sulfate solution. Determine the molar concentration of sodium cations in the resultant mixture.


2. The attempt at a solution
Moles of sodium ions in sodium hydroxide = 0.200 x (15/1000) = 0.003 mol
Let volume of sodium sulfate be Vx.
(0.120Vx) x 2 + 0.003 = Total moles of sodium ions

After which, i find it hard to proceed. :(
 
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You started with 15 mL, now you have 100 mL. How many mL were added?
 
85 mL? But I remember that particles can fit into small spaces, so surely 85 mL is wrong?