1. The problem statement, all variables and given/known data 10.00 cm3 of 1.00 mol dm–3 sulfuric acid is fully neutralized by 20.00 cm3 of 1.00 mol dm–3 of sodium hydroxide. What is the concentration, in mol dm–3, of sodium sulfate solution produced by the reaction? A 0.33 B 0.50 C 0.67 D 1.00 Correct answer = A 2. Relevant equations Mol = Concentration * Volume (dm^3) 3. The attempt at a solution I calculated the number of moles of sodium sulfate which are 0.01 mol from the formula and ratio between the moles of sulfuric acid:sodium sulfate or sodium hydroxide:sodium sulfate. We dont have the volume of sodium sulfate. If i take the volume as 30 cm^3 for sodium sulfate then i get the correct answer A but water is present too so thats not possible, please explain!