Solving dy/dx = sinh(ux/t₀) for y

[scrapironryan]

Hi all,
Im new to this and i can't work this out,
dy/dx=sinh(ux/to)
I need to determine the formula for y?
any help will be greatful.

 

[CompuChip]

What are u, t and o, are they just constants?
In that case, you can simply integrate both sides, using that $$\int \sinh(x) \, dx = \cosh(x) + c$$.