Solving dy/dx = sinh(ux/t₀) for y

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scrapironryan
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Hi all,
Im new to this and i can't work this out,
dy/dx=sinh(ux/to)
I need to determine the formula for y?
any help will be greatful.
 
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What are u, t and o, are they just constants?
In that case, you can simply integrate both sides, using that [tex]\int \sinh(x) \, dx = \cosh(x) + c[/tex].
 

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