Solving Elasticity Question: Find Height of Block Above Release

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The discussion focuses on calculating the height a 0.230 kg block rises above its release point after being compressed by a vertical spring with a spring constant of 4.75 x 103 N/m and compressed 0.058 m. The key principle to apply is the conservation of energy, where the potential energy stored in the spring converts to gravitational potential energy at the peak height. The correct equation to use is the energy conservation formula: ½kx² = mgh, where k is the spring constant, x is the compression distance, m is the mass, g is the acceleration due to gravity, and h is the height above the release point.

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A 0.230 kg block on a vertical spring with spring constant of 4.75 103 N/m is pushed downward, compressing the spring 0.058 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above the point of release?

I have some equations in front of me but i don't know which one to use because it seems none of them have to do with height. Can anyone help me?
 
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Try conservation of energy.
 

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