Solving Electric Fields in Surface Charge Density Problems

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SUMMARY

The discussion focuses on solving electric field problems related to surface charge density, specifically addressing a scenario involving a large horizontal sheet with a hole. The principle of superposition is confirmed as a valid method to calculate the total electric field by subtracting the field of a disc from that of the sheet. Additionally, it is established that the electric field doubles when the same charge is placed on the surface of a conductor due to the arrangement of charges inside the conductor, which results in a net internal field of zero and reinforces the external field.

PREREQUISITES
  • Understanding of electric fields and surface charge density
  • Familiarity with the principle of superposition in electrostatics
  • Knowledge of Gaussian surfaces and their application in electrostatics
  • Concept of charge distribution in conductors and its effects on electric fields
NEXT STEPS
  • Study the application of the principle of superposition in electrostatics
  • Learn about Gaussian surfaces and how to apply them to different charge distributions
  • Investigate the behavior of electric fields in conductors and insulators
  • Explore advanced problems involving electric fields and surface charge density
USEFUL FOR

Students and professionals in physics, particularly those focusing on electromagnetism, as well as educators seeking to enhance their understanding of electric fields in surface charge density problems.

latentcorpse
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ok if you could just tell em if this sounds alright.

(i) A large horizontal sheet of surface charge density \sigma has a hole of radius b count out of it. Find the electric field directly above the centre of the hole.

I already have expressions for the electric field due to the sheet and the disc of radius b on their own - can i just use the principle of superposition to subtract the field of the disc of radius b from the field of the sheet to get the total electric field?

(ii) By applying a Gaussian pillbox to an infinitely large charged sheet of surface charge density \sigma, I obtained \vec{E(z)} = \frac{\sigma}{2 \epsilon_0} \vec{z} for the electric field. I am now asked why this field would double if the same charge were placed on the surface of a conductor.

I have a feeling this is because in the conductor the charges inside arrange themselves to give a net internal field of 0 and then this arrangement of the charges would cause a field to be generated outside the conductor equal to the initial external field, hence doubling it as a result of the superposition principle.

How do these ideas sound?
 
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latentcorpse said:
... can i just use the principle of superposition to subtract the field of the disc of radius b from the field of the sheet to get the total electric field?
Of course you can.
 

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