MHB Solving Equation: x = sqrt(3x + x^2 - 3sqrt(3x + x^2))

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The equation x = sqrt(3x + x^2 - 3sqrt(3x + x^2) is solved by first squaring both sides, leading to x^2 = 3x + x^2 - 3sqrt(3x + x^2). Simplifying this results in -3x = -3sqrt(3x + x^2), which further simplifies to x = sqrt(3x + x^2). Squaring again gives x^2 = 3x + x^2, leading to the conclusion that 0 = 3x. The only real solution is x = 0, confirming the correctness of the solution process.
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Find all real solutions of the equation.

$x = \sqrt{3x + x^2 - 3\sqrt{3x + x^2}}$

Must I square each side twice to start?

$(x)^2 = [\sqrt{3x + x^2 - 3\sqrt{3x + x^2}}]^2$

$x^2 = 3x + x^2 - 3\sqrt{3x + x^2}$

$x^2 - x^2 - 3x = -3\sqrt{3x + x^2}$

$-3x = -3\sqrt{3x + x^2}$

$x = \sqrt{3x + x^2}$

$(x)^2 = [\sqrt{3x + x^2}]^2$

$x^2 = 3x + x^2$

$x^2 - x^2 = 3x$

$0 = 3x$

$0/3 = x$

$0 = x$

Is this right?
 
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Yes, it's correct.
 
Good to know that I am right.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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