Solving Equilibrium Problem: PCl5 <--> PCl3 + Cl2

Thread starter tornzaer
Start date Jun 4, 2008
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Equilibrium

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SUMMARY

The equilibrium problem involves the reaction PCl5(g) <-----> PCl3(g) + Cl2(g) with an initial amount of PCl5 at 0.40 mol in a 10.0 L flask. Given that the equilibrium concentration of Cl2 is 0.25 mol, the equilibrium constant (Ke) can be calculated using the formula Ke = [PCl3][Cl2]/[PCl5]. After determining the changes in concentrations at equilibrium, the final concentrations can be used to find Ke definitively.

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Jun 4, 2008

tornzaer

Hi, I have no clue how to solve this problem:

Given that the initial n of PCl5 is 0.40 mol and the equilibrium n of Cl2 = 0.25 mol for the following equilibrium in a 10.0 L flask, find the Ke for these conditions.

PCl5(g) <-----> PCl3(g) + Cl2(g)

Thanks a lot of your help. :)