Solving Esther's Morning Commute Problem

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Homework Help Overview

The problem involves Esther's morning and evening commute, where she drives to work at different average speeds and the total commuting time is given. The objective is to determine the distance driven in the morning.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relationships between the time taken in the morning and evening, represented by variables p and q. There are attempts to set up equations based on average speeds and total time, with some questioning the arithmetic steps taken.

Discussion Status

There are multiple interpretations of the calculations, with some participants pointing out potential errors in the arithmetic and questioning the logic behind certain steps. While some numerical answers are acknowledged as correct, there is no explicit consensus on the final distance calculation.

Contextual Notes

Participants note that the problem involves commuting times and speeds, and there is an emphasis on the total time constraint of one hour. There are also discussions about the appropriateness of simplifying fractions in the equations.

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Homework Statement


Esther drove to work in the morning at an average speed of 40 miles per hour. She returned home in the evening along the same route and averaged 30 miles per hour. If Esther spent a total of one hour commuting to and from work how many miles did Esther drive to work in the morning?



Homework Equations





The Attempt at a Solution


40(time she took in the morning, or p) = x
30(time she took in the evening, or q) = x

Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.

Therefore 8(60-q) = 6q or 480-9q = 6q. So 480 = 14q, which makes q = 34.2857 If q = 34.2857, then by (p+q)=60, p (the time she took in the morning) must equal 25.714285.
Then (25.714285/60) x 40 = 23.80 miles I think

Am I correct?
 
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maria vega said:
Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

It's not worth the fraction of a second it takes to divide by 2 and get 4p = 3q?
maria vega said:
Therefore 8(60-q) = 6q or 480-9q = 6q.

Where did the 9 come from?

EDIT: Just realized you canceled out that mistake with another one by saying that the sum of the q terms was 14q (the correct answer) even though what you wrote would have yielded 15q as a result.

EDIT 2: Although your numerical answers for p and q seem correct, your final answer for the distance is not correct.
 
Last edited:
ok Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.

Therefore 8(60-q) = 6q or 480-8q = 6q. So 480 = 14q, which makes q = 34.2857 If q = 34.2857, then by (p+q)=60, 30 x (34.825/60) = 17.1425 is this it? the distance of his house to the office
 
maria vega said:
ok Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

LOL. This doesn't make any more sense than it did the first time you wrote it. They're both even numbers. It takes almost no time for the extra step of dividing them by 2.

maria vega said:
Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.

Therefore 8(60-q) = 6q or 480-8q = 6q. So 480 = 14q, which makes q = 34.2857 If q = 34.2857, then by (p+q)=60, 30 x (34.825/60) = 17.1425 is this it? the distance of his house to the office

Yeah, that answer seems about right.
 
thank youuu!
 

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