How Do You Prove f^(2n)(0)=(2n)!/(n!) for f(x)=e^(x^2)?

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SUMMARY

The discussion focuses on proving the equality f^(2n)(0)=(2n)!/(n!) for the function f(x)=e^(x^2). Participants suggest starting by expressing f(x) as an infinite series using the series expansion of e^x. This approach allows for a comparison with the Taylor expansion of a general function around x=0, which is essential for deriving the desired result.

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  • Understanding of Taylor series expansion
  • Familiarity with the exponential function series expansion
  • Knowledge of factorial notation and its properties
  • Basic calculus concepts related to derivatives
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  • Study the Taylor series expansion of functions around x=0
  • Learn about the series expansion of the exponential function e^x
  • Explore the properties of factorials and their applications in combinatorics
  • Practice deriving derivatives of functions using Taylor series
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Students in mathematics, particularly those studying calculus and series expansions, as well as educators looking to enhance their understanding of function behavior near specific points.

leftwing1018
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Here's the problem:

If f(x)=e^(x^2), show that f^(2n)(0)=(2n)!/(n!).

Really I don't even know where to begin. Any help on where to start would be great.
 
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Hi leftwing1018,

Welcome to PF. Here's a hint: write f(x) as an infinite series using the well-known series expansion of ex, and then compare that with the Taylor expansion of a general function near x = 0.
 

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