Solving Farmer Lever Problem | Min Force Needed

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SUMMARY

The farmer lever problem involves calculating the minimum force required to lift a 210kg rock using a lever with a fulcrum positioned between the rock and the handle. Given that the distance from the lever's handle to the fulcrum (l1) is nine times the distance from the fulcrum to the rock (l2), the solution employs elementary algebra to derive the force. The minimum force exerted by the farmer is calculated to be 233.3 Newtons (N).

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A farmer uses a lever to list a 210kg rock so he can remove it from the field. The distance, l1, from the lever's handle to the fulcrum is 9 times the distance, l2, from the fulcrum to the rock.
Assume: the fulcrum is between the rock and the handle. the weight of the lever is negligible.
What is the minimum force the farmer must exert on the lever in order to lift the rock?

I have no idea how to approach this problem. Can anyone give me some pointers so i can look for stuff in my book or online. what section would this kind of problem fall in.

thanks in advance
 
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Why not google on "using levers with fulcrum" (omit the quotes) ?
 
donjt81 said:
A farmer uses a lever to list a 210kg rock so he can remove it from the field. The distance, l1, from the lever's handle to the fulcrum is 9 times the distance, l2, from the fulcrum to the rock.
Assume: the fulcrum is between the rock and the handle. the weight of the lever is negligible.
What is the minimum force the farmer must exert on the lever in order to lift the rock?
I have no idea how to approach this problem. Can anyone give me some pointers so i can look for stuff in my book or online. what section would this kind of problem fall in.
thanks in advance

It is not hard if you use elementary algebra ...
Let x be the distance from rock to fulcrum, then 9x is from handle to fulcrum

Hence, F times 9x = 2100x

F = 233.3N
 

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