- #1

Arooj

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## Homework Statement

A 100g piece of ice at 0.0°C is dropped into 500g of water at 100°C. What is the final temperature of mixture.

## Homework Equations

Q=mL (latent heat)

Q=mcΔt

Qw=-Qx (energy absorbed by water is equal but opposite to that of substance inserted into water)

specific heat ice: 2.09 * 10^3 J/kg * °C

specific heat water: 4.186 * 10^3 J/kg * °C

specific heat steam: 2.01 * 10^3 J/kg * °C

latent heat of fusion: 3.33 * 10^5 J/kg

latent heat of vaporization: 2.26 * 10^6 J/kg

## The Attempt at a Solution

Do you find the total heat including phase change heat for both substances, using final temperature as an unknown variable? If so:

Q = mcΔt + mL

Qw = (0.5 *4.186 * 10^3 *(Tf-100)) + 0.5 * 2.26 * 10^6

Qx= -((0.5 *4.186 * 10^3 *(Tf-0)) + (0.5 * 3.33 * 10^5))

I set both equal after simplifying, and obtained a final temperature of 264.14°C, which is too bizarre of an answer.