- #1

sciencegeek101

- 8

- 0

Vf= 20m/s

Vi= 0m/s

a=9.8m/s2

Δd= 40m

Δd=?

Vf2=Vi2+2aΔd

Vf=velocity final

Vi= velocity initial

a= acceleration

Δd= displancement

(rearrange the equation)

Δd= (Vf2-Vi2) / 2a

Δd= (20^2-o^2) / 2x9.8

Δd= 400/19.6

Δd= 20.4m

∴ the stone was 20.4m above the water surface when Jamilla threw it

Not sure if i am doing this correctly?

Much thanks in advance to those who help me out!