Solving for Domain and Asymptotes in Functions f(x) and g(x)

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Homework Help Overview

The discussion revolves around determining the domain and asymptotes for the functions f(x) and g(x), specifically focusing on logarithmic and linear functions. The original poster presents two functions, f(x) = -log3(x – 1) + 2 and g(x) = 3 - x + 1 - 9, and requests assistance in finding their respective domains, asymptotes, and intercepts.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss how to find the domain of logarithmic functions, particularly addressing the conditions under which logarithms are defined. There is an exploration of the implications of the logarithmic function in determining the domain.

Discussion Status

Some participants are actively engaging with the problem, providing insights into how to approach the domain of logarithmic functions. There is a recognition of confusion regarding the domain when logarithms are involved, and guidance has been offered to clarify this aspect.

Contextual Notes

Participants are navigating the complexities of logarithmic functions and their domains, indicating that the original poster may have specific constraints or misunderstandings related to logarithmic properties.

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Please Help with Domain...

Homework Statement



For f(x) Determine Domain, Vertical Asymptote and x and y intercepts. then State and graph the effect of the modifications and sketch the graph of f(x)
Given f(x) = - log3(x – 1) + 2


For g(x) determine domain, Horizontal asymptote and x and y intercepts. then state and graph the effect of the modifications and sketch the graph of g(x)
Given g(x) = 3 - x + 1 - 9
 
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Lets begin with the first problem. To find the domain, consider when the log of something not exist. Let me know if this is what's confusing you.
 
yes that is a confusing part, I know how to find the Domain, but not when involving log
 
Ok, so let's say I have y = log( 2 - x) - 1, and I want to find the domain of the function. You should know that the log of zero, or any negative quantity does not exist. So I would set the function inside of the log equal to zero:

2 - x = 0 ---> x = 2.

Now I know that the function exists as long as x is greater than 2. It does not exist when x is two or less. This is our domain. Does that make sense?
 
yes thank you.
 

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