Solving for Horsepower w/ Unfamiliar Equation

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SUMMARY

The discussion focuses on calculating horsepower developed by a Niagara turbine using a specific equation. The formula used is Php = mmin h g / 33,000, where Php represents horsepower, mmin is the mass flow rate in pounds per minute, h is the head in feet, and g is the acceleration due to gravity. The user calculated a mass flow rate of 13,880.4 lb/min and derived a horsepower output of 8,862.42 hp. The discussion also highlights the importance of using the correct conversion factors and suggests utilizing the Unit Conversion add-in for Excel to simplify unit conversions.

PREREQUISITES
  • Understanding of horsepower calculations and related equations
  • Familiarity with unit conversions, particularly between imperial and SI units
  • Knowledge of fluid dynamics, specifically mass flow rate and head
  • Basic proficiency in using Excel for calculations and conversions
NEXT STEPS
  • Research the principles of fluid dynamics and how they relate to horsepower calculations
  • Learn about unit conversion techniques, especially between imperial and metric systems
  • Explore the use of the Unit Conversion add-in for Excel for efficient calculations
  • Study the implications of using different values for acceleration due to gravity in calculations
USEFUL FOR

Students in engineering or physics, educators teaching fluid dynamics, and professionals involved in hydraulic systems or turbine design will benefit from this discussion.

kriegera
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Homework Statement


My teacher assigned a horsepower problem except that we never covered horsepower. Here's my attempt:

One of the Niagara turbines uses 172,000 cubic feet of water per minute under a head of 215 ft. What is the horsepower developed?



Homework Equations





The Attempt at a Solution



The total horsepower developed by water falling from a given height is the product of the mass flow rate in pounds per minute times the falling height in feet divided by 33,000. It can be expressed as:
Php = mmin h g / 33000
where
Php = power (horsepower, hp)
mmin = mass flow rate per minute (lbm/min)
h = head or height (ft)
g = acceleration of gravity (32 ft/s2)

Convert 172,000 cubic feet of water per minute to pounds per minute: A cubic foot of air is approximately 0.0807 lbs  (172,000)(0.0807)=13880.4 lb/minute
Php = (13,880.4)(215)(9.8) / 33000= 8,862.42 hp

-Am I on track here? Also, I used 9.8 for acceleration of gravity-can anyone tell me if this is the value I should be using? Thanks!
 
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Your equation makes a lot of sense, but I'm not sure about the conversion factors. I don't remember what the 33 000 conversion factor includes but in the SI units:

P = \dot{m}gh

Where the units are:

P --> W
\dot{m} --> kg/s
g --> 9.81 m/s²
h --> m

The mass flow rate is equal to the volumetric flow rate (m³/s) times the density of water (1000 kg/m³), not air.
 
I know, it is super useful to have memorized all the conversion factors. But, once you understand what is happening there are tools that make unit conversion awesome! One of the best ones I've found is the Unit Conversion in Excel (http://www.unitconversionaddin.com ). This simply works because you ( a student like me) are able to do the unit conversion automatically in excel like a program. You don't have to either search on the internet for the conversion value or have to write out some excel function. The download is like 5 bucks and has saved me hours of stress and time. The conversions are really detailed and accurate too, like to 5 decimal places where applicable.
 
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