MHB Solving for $k$: Digit Product = $\dfrac{25k}{8}-211$

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The discussion focuses on finding positive integers \( k \) such that the product of the digits of \( k \) equals \( \frac{25k}{8} - 211 \). Participants confirm that both 72 and 88 satisfy this equation. There is a suggestion to share the solution with MHB for further insights. The conversation emphasizes the importance of verifying the conditions for \( k \) to ensure all solutions are identified. Overall, the thread highlights a mathematical exploration of digit products in relation to a linear equation.
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Find all positive integers $k$ such that the product of the digits of $k$, in the decimal system, equals $\dfrac{25k}{8}-211$.
 
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72 and 88
 
Yes, your answer is correct. Do you think you can share with MHB of your solution?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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