Solving for k in e^10k = 0.75

[ziddy83]

Ok sorry for this..small, stupid obvious question...but here it is..

i need to solve for k in:

e^10k = .75

So do i just take the natural log of both sides...and then the 10k should come down and i can just solve for k from that, right?

 

[Data]

Yes.

Unfortunately this board won't let me make a four letter reply, so I have to add this pointless line :)

 

[ziddy83]

ok great..thanks a lot..