Solving for k & P0: 5 Decimal Places of Accuracy

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The discussion focuses on solving the equations 1150 = P0exp(2k) and 11500 = P0exp(8k) to find the values of k and P0 with specified accuracy. The user initially struggled with variable cancellation during substitution but later realized that dividing one equation by the other effectively eliminates P0, simplifying the problem. The correct approach leads to determining k with five decimal places of accuracy and P0 with two decimal places of accuracy.

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From the facts that 1150 = P0exp(2 k) and 11500 = P0exp(8 k) we can solve for k and P0. Provide at least five decimal places of accuracy for k and at least two decimal places of accuracy for P0.

I've got
P0 = 1150/e^2k
and
P0 = 11500/e^8k

but when i try to solve for any variable by substituting I keep ending up cancelling out all the variables
help!

thanks
 
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nvm i had crazy algebra
 
Dividing one equation by the other eliminates P0.
 

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