Solving for Side Length of Right Pyramid with Height/Volume

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SUMMARY

The discussion focuses on calculating the side length of a right pyramid with a given volume of 554.9 cubic units and a height of 15.1 units. The formula for the volume of a pyramid, V = (1/3)lwh, is utilized, leading to the rearrangement for base area as lw = 3V/h. When the base is assumed to be square, the side length can be determined using the formula s = √(3V/h), resulting in a specific calculation for the side length.

PREREQUISITES
  • Understanding of geometric formulas, specifically for pyramids.
  • Familiarity with algebraic manipulation of equations.
  • Knowledge of square roots and their application in geometry.
  • Basic concepts of volume measurement in three-dimensional shapes.
NEXT STEPS
  • Calculate the side length of a square pyramid using the formula s = √(3V/h) with the given values.
  • Explore the implications of varying base shapes on the volume of pyramids.
  • Study the derivation of the volume formula for different types of pyramids.
  • Investigate real-world applications of pyramid volume calculations in architecture and design.
USEFUL FOR

Students studying geometry, educators teaching volume calculations, and anyone interested in mathematical problem-solving related to three-dimensional shapes.

Shannog
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Homework Statement



Basically the volume of the pyramid is 554.9 and its height is 15.1. I know that the formula to find the volume of a pyramid is V=1/3lwh but I'm too dumb to figure out how to switch it around to make it work.

The Attempt at a Solution



I don't even know where to start!
 
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V= (1/3)lwh is the volume of a pyramid with rectangular base with side lengths l and w and height h. If you know the volume of the pyramid, V, and height l, then you can solve for the base area as lw= 3V/h. You cannot solve for l and w separately- they can be any numbers that multiply to give 3V/h. If you know the base is square, with side lengths l= w= s, you have s^2= 3V/h then s= \sqrt{3V/h}.
 
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