Solving for Tension in Elevator Cable: 2300 kg, 50 m, 12 m/s

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SUMMARY

The discussion focuses on calculating the tension in the supporting cable of an elevator with a combined mass of 2300 kg, which is brought to rest from a downward speed of 12 m/s over a distance of 50 m. The solution involves determining the acceleration using kinematic equations and then applying Newton's second law to find the tension in the cable. The key equations include the kinematic equation for acceleration and the force equation to derive the tension.

PREREQUISITES
  • Understanding of kinematic equations for motion
  • Familiarity with Newton's second law of motion
  • Basic knowledge of forces and tension in cables
  • Ability to perform calculations involving mass and acceleration
NEXT STEPS
  • Learn how to apply kinematic equations to solve for acceleration in motion problems
  • Study Newton's second law and its application in tension calculations
  • Explore real-world applications of tension in cables and lifting systems
  • Investigate the effects of varying mass and acceleration on tension in similar scenarios
USEFUL FOR

Students in physics or engineering courses, particularly those studying mechanics, as well as professionals involved in elevator design and safety analysis.

tjbateh
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Homework Statement


An elevator and its load have a combined mass of 2300 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 50 m.


Homework Equations





The Attempt at a Solution


Any idea how to approach this problem?
 
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Hi tjbateh! :wink:

This question is in two parts, a maths part and a physics part.

The maths is to find the acceleration.

The physics is then to find the force.

What is the acceleration? :smile:
 

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