Solving for the equation or the problem?Solving a Calculus Equation: Help Needed

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The discussion centers on solving a mathematical problem involving integration, specifically the equation formulated as -MA*1 + RA * (1^2)/2 - 29.43 * 0.4 - 19.62 * 0.85. The user seeks assistance in achieving a solution similar to another equation provided, which is -MA * 20 + RA * (20^2)/2 - (20^3)/8 + (10^3)/8 - 6 * 5^2 = 0, resulting in 10Ra - Ma = 205/4. The conversation highlights a misunderstanding of the problem's classification, as it was deemed unrelated to calculus or differential equations.

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bakoo
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Hey, need some help on a problem, think its classed as integration, but may be wrong?

I have formulated this equation, but don't know how to get to the next step

[tex]\therefore\: -MA*1 + RA \frac{1^2}{2} - 29.43 * 0.4 - 19.62 * 0.85[/tex]


This is a similar equation that has been solved

[tex]\therefore -\;MA * 20 + RA * \frac{20^2}{2}- \frac{20^3}{8} + \frac{10^3}{8} -6 * 5^2\;=\;0[/tex]

and here is the solution

[tex]\displaystyle \therefore\;\;\;\;\;\;10\;R_a\;-\;M_a\;=\;\frac{205}{4}[/tex]


----

I don't know, and can't figure out how to achieve this result for the top formula? Calculus is not my strong point at all.

This is not homework, this is related to a problem i am trying to solve.

Thanks for any help
 
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I would recommend that you first take the time to write out the problem. What you have is NOT an equation and you give no idea WHAT you want to do.

Also, because this has nothing to do with either calculus or differential equations, I am moving it to the "general math" section.
 

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