Solving for Time in Scalar Product Equation

[kkershaw]

Homework Statement

I am solving for t using this equation: d = !(v + 0)t;
My d=.984 and v=1.9
I don't know what to do with the "!"

Homework Equations

d = !(v + 0)t;

The Attempt at a Solution

In a problem with different numbers I was able to solve for t by dividing and ignoring the "!", then multiply by 2 for the answer.
.984/1.9= .518
.518 * 2 = 1.036 but this does not work.

 

[lanedance]

hi kkershaw

not too sure what you're trying to do - can you explain the whole problem...?

 

[LowlyPion]

Homework Statement

I am solving for t using this equation: d = !(v + 0)t;
My d=.984 and v=1.9
I don't know what to do with the "!"

Are you sure it's not

d = |(v + 0)t| ?

expressing d as a scalar product of velocity (speed) and time?