Solving for work Power equations

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SUMMARY

The discussion focuses on calculating the work done by Lance Armstrong during a 155-km race in the Tour de France, where he generates an average power of 6.50 W/kg. Using the formula for average power (P = W/t) and kinetic energy (KE = 1/2 mv^2), the total work done is calculated to be approximately 6,143,292.68 joules. When converted to nutritional Calories, this amount equates to approximately 1,466.85 Calories, with some participants noting slight variations in rounding.

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eanderson
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Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generated by Lance Armstrong (m = 75.0 kg) is 6.50 W per kilogram of his body mass. (a) How much work does he do during a 155-km race in which his average speed is 12.3 m/s? (b) Often, the work done is expressed in nutritional Calories rather than in joules. Express the work done in part (a) in terms of nutritional Calories, noting that 1 joule = 2.389 x 10-4 nutritional Calories.

(avg)P=w/t

ke=1/2mv^2

w=KEf - KEi

(avg)P= F * S(avg)
 
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the answer for those numbers is:

A: 6143292.682926829 J
B: 1466.846 Calories
 
eanderson said:
the answer for those numbers is:

A: 6143292.682926829 J
B: 1466.846 Calories

Looks good. watch the rounding though... I'm getting 1467.6 calories...
 

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