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4x[tex]^{2}[/tex] + 4x - 48 = 0

Here's what I've done to solve so far:

4(x[tex]^{2}[/tex] - 1x - 12) = 0

4(x-4)(x+3)=0

Now I'm not even sure if what I'm doing is right here, but if it is my problem is comming to the solution set itself - I'm really just not sure what to do with that initial 4.