Solving Fourier Transform of f(x)=β2/(β2+x2)

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SUMMARY

The discussion focuses on finding the Fourier transform of the function f(x) = β²/(β² + x²). The Fourier transform is defined by the equation F(k) = (1/√(2π)) ∫(−∞ to ∞) e^(−ikx)f(x) dx. The user encounters difficulties during integration after applying partial fractions, leading to the expression F(k) = (β²/√(2π)) ∫(−∞ to ∞) (e^(−ikx)/(β² + x²)) dx. The recommended solution involves utilizing the residue theorem to simplify the integration process.

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Homework Statement


I have to find the Fourier transform of

[tex]f(x)=\frac{\beta^2}{\beta^2+x^2}[/tex]


Homework Equations


Fourier Transform is given by

[tex]F(k) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{\infty} e^{-ikx}f(x) dx[/tex]

The Attempt at a Solution


I'm having trouble with the integration after I separate into two integrals using partial fractions:

[tex]F(k)=\frac{\beta^2}{\sqrt{2\pi}}\int_{-\infty}^{\infty} \frac{e^{-ikx}}{\beta^2+x^2}dx[/tex]

Note
[tex]\frac{1}{\beta^2+x^2}=\frac{1}{2i\beta} \left( \frac{1}{x-i\beta} - \frac{1}{x+i\beta} \right)[/tex]

[tex]F(k)=\frac{1}{\sqrt{2\pi}} \frac{\beta}{2i} \left[ \int_{-\infty}^{\infty} \frac{e^{-ikx}}{(x-i\beta)} dx - \int_{-\infty}^{\infty} \frac{e^{-ikx}}{(x+i\beta)} dx \right][/tex]


Are there any suggestions on how to proceed?
 
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Use the residue theorem.
 
excellent advice, thank you
 

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