Solving Friction and Weight Problem: W=75lbs

  • Thread starter Thread starter Bradracer18
  • Start date Start date
  • Tags Tags
    Friction Weight
Click For Summary
SUMMARY

The discussion focuses on solving a physics problem involving a 100lb drum, a lightweight rope, and a weight, W, with a coefficient of friction of 0.50. The maximum weight that can be supported by this arrangement is determined to be W=75lbs. Key equations include the balance of forces in both the x and y directions, as well as the application of Coulomb's law of friction to establish relationships between the forces. The solution involves taking moments about the center of the drum to derive additional equations necessary for solving the problem.

PREREQUISITES
  • Understanding of static equilibrium in physics
  • Familiarity with Coulomb's law of friction
  • Ability to set up and solve equations involving forces and moments
  • Knowledge of basic mechanics, specifically rotational dynamics
NEXT STEPS
  • Study the principles of static equilibrium in detail
  • Learn how to apply Coulomb's law of friction in practical scenarios
  • Explore methods for taking moments in mechanical systems
  • Practice solving problems involving forces and torques in rotational dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of problem-solving in static equilibrium and friction scenarios.

Bradracer18
Messages
203
Reaction score
0

Homework Statement



A lightweight rope is wrapped around a 100lb drum, passes over a frictionless pulley, and is attached to weight, W. The coefficient of friction is 0.50. Determine the maximum amount of weight that can be supported by this arrangement.

I've drawn a picture, showing what I think are the forces on everything.

I need help solving this, as I'm not sure how to actually do it. The answer, I have(given to me) is W=75lbs.

Homework Equations





The Attempt at a Solution



Forces in x direction = 0 = Fa - Nb + Tw
Forces in y direction = 0 = Na + Fb - 100

Not sure if there is a moment(and if so, where do I take it about)...also, if not...I'm not sure how to solve this next.

Thank you,
Brad
View attachment friction.bmp
 
Physics news on Phys.org
Why not take moments about the center of the drum? Hint: If the drum is just about to turn, what can you say about the friction forces?
 
You have 5 unknowns Fa Na Fb Nb and Tw so you need 5 equations.

You have 2 equations already.

When the drum starts to rotate, Coulombs law of friction says
Fa = mu.Na and Fb = mu.Nb That makes 4 equations.

You can get a 5th equation by taking moments. If doesn't matter where you take moments about. Choose a point which several forces pass through, so they have zero moment and you get a simpler equation.
 
Ok...so now, I took the moment about the center.

Counterclockwise

M = 0 = Fb(d/2) + Fa(d/2) - Tw(d)

And the 2 equations above. I'm totally lost as to how I mathematically solve these though, or where I start. Also, I don't know the diameter(d)...so not sure how the moment equation will help...
 
Bradracer18 said:
Ok...so now, I took the moment about the center.
Good.

Counterclockwise

M = 0 = Fb(d/2) + Fa(d/2) - Tw(d)
Why is one force times d while others are times d/2?

And the 2 equations above. I'm totally lost as to how I mathematically solve these though, or where I start. Also, I don't know the diameter(d)...so not sure how the moment equation will help...
The d drops out, so you don't need the actual value.

If you answer my question/hint about friction, you'll be able to rewrite Fb and Fa in terms of Nb and Na. (Similar to what AlephZero told you to do.) Then you'll have 3 equations and 3 unknowns--solve!
 
Ok...I was saying it was the diameter/2...or the radius. I don't know what I was thinking...I found that mistake, and will try to solve it now...see if I can do it...not sure.
 
yes, I did solve it(it feels good...haha). Thank you for all of your help, I sure appreciate it!
 

Similar threads

  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 13 ·
Replies
13
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
13
Views
2K