1. The problem statement, all variables and given/known data How much work is done by friction when a box with an apparent mass of 325kg moves horizontally across a floor with coefficient of friction of .33 and is pulled at 59.9 degree angle for 2.60 m? What is the force that is pulling the box? 2. Relevant equations W=Fdcos@ (@= theta) Fnet=ma 3. The attempt at a solution I searched for what apparent mass was, but what I found seemed to do with volume and water displacement, which aren't related to this problem. Instead I tried solving the second question first because I needed Normal force to solve the work done by friction. For my free body diagram, I had force applied (Fa) in the y direction upwards on the y axis along with normal force. Along the negative y axis I had weight. Force of friction (Ff) was along the negative x axis, and force applied in the x direction was on the positive x axis. In the x direction... Ff=Facos@ (since no acceleration) uN = FaCos@ In the y direction... Fasin@ + N = W (again since no acceleration) N= mg - FaSin@ So plugging in,,, u(mg-Fasin@) = FaCos@ Solving for Fa I got... umg-uFasin@ = Facos@ Fa= umg/(usin@ + cos@) Fa= (.33*325 kg*9.8)/(.33sin59.9+cos59.9) Getting that the force applied = 1335.50 N, but this is not correct. Any help would be appreciated, thanks in advance.