Solving Friction and Weight Problem: W=75lbs

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Homework Help Overview

The problem involves a lightweight rope wrapped around a 100lb drum, passing over a frictionless pulley, and attached to a weight, W. The coefficient of friction is given as 0.50, and the goal is to determine the maximum weight that can be supported by this system.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the forces acting on the system and the equations of equilibrium. There is a suggestion to take moments about the center of the drum to analyze the problem further. Some participants raise questions about the relationship between the forces and the friction involved, as well as the implications of the drum's rotation.

Discussion Status

The discussion has progressed with participants offering hints and guidance on how to approach the problem, including the need for additional equations to solve for the unknowns. There is an acknowledgment of confusion regarding the mathematical steps needed to solve the equations, but some participants express a sense of progress and understanding as they work through the problem.

Contextual Notes

Participants note the absence of certain values, such as the diameter of the drum, which complicates the moment equation. There is also a recognition of the need to clarify the definitions and relationships between the forces involved.

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Homework Statement



A lightweight rope is wrapped around a 100lb drum, passes over a frictionless pulley, and is attached to weight, W. The coefficient of friction is 0.50. Determine the maximum amount of weight that can be supported by this arrangement.

I've drawn a picture, showing what I think are the forces on everything.

I need help solving this, as I'm not sure how to actually do it. The answer, I have(given to me) is W=75lbs.

Homework Equations





The Attempt at a Solution



Forces in x direction = 0 = Fa - Nb + Tw
Forces in y direction = 0 = Na + Fb - 100

Not sure if there is a moment(and if so, where do I take it about)...also, if not...I'm not sure how to solve this next.

Thank you,
Brad
View attachment friction.bmp
 
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Why not take moments about the center of the drum? Hint: If the drum is just about to turn, what can you say about the friction forces?
 
You have 5 unknowns Fa Na Fb Nb and Tw so you need 5 equations.

You have 2 equations already.

When the drum starts to rotate, Coulombs law of friction says
Fa = mu.Na and Fb = mu.Nb That makes 4 equations.

You can get a 5th equation by taking moments. If doesn't matter where you take moments about. Choose a point which several forces pass through, so they have zero moment and you get a simpler equation.
 
Ok...so now, I took the moment about the center.

Counterclockwise

M = 0 = Fb(d/2) + Fa(d/2) - Tw(d)

And the 2 equations above. I'm totally lost as to how I mathematically solve these though, or where I start. Also, I don't know the diameter(d)...so not sure how the moment equation will help...
 
Bradracer18 said:
Ok...so now, I took the moment about the center.
Good.

Counterclockwise

M = 0 = Fb(d/2) + Fa(d/2) - Tw(d)
Why is one force times d while others are times d/2?

And the 2 equations above. I'm totally lost as to how I mathematically solve these though, or where I start. Also, I don't know the diameter(d)...so not sure how the moment equation will help...
The d drops out, so you don't need the actual value.

If you answer my question/hint about friction, you'll be able to rewrite Fb and Fa in terms of Nb and Na. (Similar to what AlephZero told you to do.) Then you'll have 3 equations and 3 unknowns--solve!
 
Ok...I was saying it was the diameter/2...or the radius. I don't know what I was thinking...I found that mistake, and will try to solve it now...see if I can do it...not sure.
 
yes, I did solve it(it feels good...haha). Thank you for all of your help, I sure appreciate it!
 

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