Biology Solving Genetics Problem: Y-Linked Recessive Trait Inheritance

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The discussion revolves around understanding the inheritance of a trait, initially thought to be Y-linked recessive, but later clarified as X-linked recessive due to the absence of affected males. Participants identify heterozygous individuals in a pedigree and calculate probabilities for carriers and offspring traits, concluding that III-2 has a 50% chance of being a carrier and III-3 and III-4's child has a 25% chance of inheriting the trait. The use of Punnett squares is recommended for visualizing genetic probabilities. The conversation emphasizes the importance of correctly identifying inheritance patterns to solve related genetic questions.
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My Question:
  • What is the mechanism of inheritance for the trait?
  • Which people in the pedigree are known to be heterozygous for the trait?
  • What is the probability that III-2 is a carrier( heterozygous)?
  • If III-3 and III-4 marry, what is the probability that their first child will have the trait?

Picture

View attachment Doc3.docView attachment Doc3.doc

My Answers:
  • Y-Linked recessive
  • I1, I2, II1, and II2
  • ?
  • ?
Of the answers I have so far are these correct?
Thank You :smile:
 
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Are you using the usual convention that males are represented by squares and females by circles? If so, how would it be Y-linked if only females are affected? If you reconsider part 1, the rest will be easier to answer once you've gotten that part.
 
Opps:blushing:
Wouldn't it be X-linked recessive since it couldn't be x-linked dominant otherwise one of the parents would of had it, right?

Also for these questions:

What is the probability that III-2 is a carrier( heterozygous)?
Answer: 50%

If III-3 and III-4 marry, what is the probability that their first child will have the trait?
Answer: 25%

Do I just need to figure them by making a punnett square based off the parents?

Thank You
 
Last edited:
jena said:
Opps:blushing:
Wouldn't it be X-linked recessive since it couldn't be x-linked dominant otherwise one of the parents would of had it, right?
Correct.

With that information, you also have to go back to your answer for the second part.

Also for these questions:
What is the probability that III-2 is a carrier( heterozygous)?
Answer: 50%
Correct.

If III-3 and III-4 marry, what is the probability that their first child will have the trait?
Answer: 25%
Do I just need to figure them by making a punnett square based off the parents?
Thank You
Yes and yes. I think you're getting the hang of this. :smile:
 
jena said:
My Question:
  • What is the mechanism of inheritance for the trait?


  • After meosis , when male and female gametes are fused , each gamete consists of a single gene. When two gamete fuse , they give genotypes which are combinations of alleles. Depending on the nature of the alleles , the phenotypes are formed. This phenotype when expressed shows the particular trait in the individual.

    [*]Which people in the pedigree are known to be heterozygous for the trait?

    People heterozygous for trait are those whose genotype for that particular trait has two alleles each of different type.


    [*]If III-3 and III-4 marry, what is the probability that their first child will have the trait?

    Draw the punnett table and see for yourself.

    BJ
 
I had a similar question, but what would the punnett square look like? Say A = dominant allele and a = recessive allele, then II1: Aa, II2: Aa (parents of III3) and II3: aa, II4: ? (parents of III4)

Would II4 be homozygous dominant (AA) since none of the children have it?

My question also asks to determine the probability using "the law of probability that relates to the simultaneous occurrence of independent events—the product law". I'm unsure of what this means...
 
Never mind about the punnett square
 
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