Solving Genetics Problem: Y-Linked Recessive Trait Inheritance

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SUMMARY

The discussion centers on the inheritance mechanism of a Y-linked recessive trait, with participants analyzing a pedigree to identify heterozygous individuals and calculate probabilities of trait expression in offspring. The correct identification of affected individuals includes I1, I2, II1, and II2 as heterozygous. The probability that individual III-2 is a carrier is established at 50%, while the likelihood that III-3 and III-4's first child will inherit the trait is determined to be 25%. The use of Punnett squares is emphasized as a method for visualizing genetic probabilities.

PREREQUISITES
  • Understanding of Y-linked and X-linked inheritance patterns
  • Familiarity with Punnett squares for genetic probability calculations
  • Knowledge of basic genetic terminology, including alleles and genotypes
  • Concept of the product law in probability related to independent events
NEXT STEPS
  • Study the principles of Y-linked inheritance and its implications in genetics
  • Learn how to construct and interpret Punnett squares for various genetic scenarios
  • Explore the product law of probability in genetics for calculating outcomes of multiple traits
  • Investigate case studies of Y-linked traits in human genetics
USEFUL FOR

Genetics students, educators, and professionals interested in understanding inheritance patterns, particularly those involving Y-linked traits and probability calculations in genetic counseling.

jena
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My Question:
  • What is the mechanism of inheritance for the trait?
  • Which people in the pedigree are known to be heterozygous for the trait?
  • What is the probability that III-2 is a carrier( heterozygous)?
  • If III-3 and III-4 marry, what is the probability that their first child will have the trait?

Picture

View attachment Doc3.docView attachment Doc3.doc

My Answers:
  • Y-Linked recessive
  • I1, I2, II1, and II2
  • ?
  • ?
Of the answers I have so far are these correct?
Thank You :smile:
 
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Are you using the usual convention that males are represented by squares and females by circles? If so, how would it be Y-linked if only females are affected? If you reconsider part 1, the rest will be easier to answer once you've gotten that part.
 
Opps:blushing:
Wouldn't it be X-linked recessive since it couldn't be x-linked dominant otherwise one of the parents would of had it, right?

Also for these questions:

What is the probability that III-2 is a carrier( heterozygous)?
Answer: 50%

If III-3 and III-4 marry, what is the probability that their first child will have the trait?
Answer: 25%

Do I just need to figure them by making a punnett square based off the parents?

Thank You
 
Last edited:
jena said:
Opps:blushing:
Wouldn't it be X-linked recessive since it couldn't be x-linked dominant otherwise one of the parents would of had it, right?
Correct.

With that information, you also have to go back to your answer for the second part.

Also for these questions:
What is the probability that III-2 is a carrier( heterozygous)?
Answer: 50%
Correct.

If III-3 and III-4 marry, what is the probability that their first child will have the trait?
Answer: 25%
Do I just need to figure them by making a punnett square based off the parents?
Thank You
Yes and yes. I think you're getting the hang of this. :smile:
 
jena said:
My Question:
  • What is the mechanism of inheritance for the trait?


  • After meosis , when male and female gametes are fused , each gamete consists of a single gene. When two gamete fuse , they give genotypes which are combinations of alleles. Depending on the nature of the alleles , the phenotypes are formed. This phenotype when expressed shows the particular trait in the individual.

    [*]Which people in the pedigree are known to be heterozygous for the trait?

    People heterozygous for trait are those whose genotype for that particular trait has two alleles each of different type.


    [*]If III-3 and III-4 marry, what is the probability that their first child will have the trait?

    Draw the punnett table and see for yourself.

    BJ
 
I had a similar question, but what would the punnett square look like? Say A = dominant allele and a = recessive allele, then II1: Aa, II2: Aa (parents of III3) and II3: aa, II4: ? (parents of III4)

Would II4 be homozygous dominant (AA) since none of the children have it?

My question also asks to determine the probability using "the law of probability that relates to the simultaneous occurrence of independent events—the product law". I'm unsure of what this means...
 
Never mind about the punnett square
 

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