Solving Half Equation Problems in Redox Reactions

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SUMMARY

This discussion focuses on the method for writing half equations in redox reactions, specifically using the example of the reaction IO3- + 5I- + 6H+ → 3I2 + 3H2O. Key steps include separating oxidation and reduction half-reactions, balancing atoms other than oxygen and water, balancing hydrogen in acidic conditions with H+, and balancing charges by adding electrons. The oxidation states of iodine species are determined to identify which undergoes oxidation and which undergoes reduction, facilitating the simplification of the final balanced equation.

PREREQUISITES
  • Understanding of redox reactions and half equations
  • Knowledge of balancing chemical equations
  • Familiarity with oxidation states and their significance
  • Concept of acidic and basic media in chemical reactions
NEXT STEPS
  • Study the process of balancing redox reactions in acidic and basic solutions
  • Learn about oxidation states and how to determine them for various elements
  • Explore examples of complex redox reactions involving multiple reactants
  • Practice writing half equations for different types of redox reactions
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Chemistry students, educators, and anyone looking to improve their skills in balancing redox reactions and understanding half equations in chemical processes.

fabbo
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I find it really hard to write half equations from the given redox reaction. I'm ok when H+ and water are not involved but when they are I get stuck.

Eg. for this reaction:

IO3- + 5I- + 6H+ ----------> 3I2 + 3H2O

How would you go about splitting it up as I features as a reactant twice?
 
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u could try these steps-
separate oxidation n reduction 1/2 reactions
balance atms other than Oxygen n water
balance H in acidic med. by adding H+ n in basic med. by adding equal no of water molecules,(ie 2H --> 2H2O) n equal no of OH- to the other side
balance charges by adding electrons
Add the two balanced reactions in such a way that the electrons are eliminated frm the reaction.

For splitting Find oxidation no of all the I containing species. oxidation takes place if it inc frm rectant to product side otherwise its reduction
 
Last edited:
Start with

IO3- -> 1/2 I2

I- -> 1/2 I2

Whatever will be in excess, will finally cancel out, or you will end with coefficients to simplify - both cases easy to deal with.
 
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