Solving Hydrate Formula w/ Titration: Na2CO3.xH20

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Discussion Overview

The discussion revolves around determining the formula of a hydrate of sodium carbonate (Na2CO3.xH2O) through titration with hydrochloric acid (HCl). Participants explore the relationships between the mass of the hydrate, the moles of Na2CO3, and the water of hydration involved in the reaction.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that the mass of the hydrate (2.316g) includes the water of hydration (xH2O).
  • Another participant clarifies that the titration results indicate the moles of Na2CO3 present, independent of the water of hydration.
  • A participant questions how to proceed after calculating the moles of Na2CO3 (0.00807906 mol) to find the formula of the hydrate.
  • There is a discussion about calculating the mass of the sodium carbonate based on the moles found.
  • One participant emphasizes the need for calculation rather than guessing the mass of sodium carbonate.

Areas of Agreement / Disagreement

Participants express some agreement on the relationship between the mass of the hydrate and the moles of Na2CO3, but there is uncertainty about the next steps in the calculation process and the interpretation of the results.

Contextual Notes

Participants have not fully resolved the calculations needed to determine the formula of the hydrate, and there are missing assumptions regarding the contributions of the water of hydration to the total mass.

Zoey Brown
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Homework Statement


The formula of a hydrate may be determined by titarion. If 2.316g of a hydrate of sodium carbonate is required to completely neutralize 38.49 mL of 0.4198 mol/L HCl,find the formula of the hydrate. The products will be NaCl, H20, and CO3

Homework Equations


n=cv
m=mM

The Attempt at a Solution


Na2CO3 . xH20 --> Solving for x
find moles of HCL
Use mole ratios
 
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You are titrating (measuring) the amount of sodium carbonate in the sample. The rest would be water (the water of hydration).
 
so does the 2.316g not include the xh2o?
 
Zoey Brown said:
so does the 2.316g not include the xh2o?

It does. But the titration result tells you how many moles of Na2CO3 are present, regardless of how much hydration water it contains.
 
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so if I've found that there are 0.00807906 mol of Na2CO3, where would i go from there to find the formula of the hydrate?
 
What is the mass of the 0.008079 moles of the sodium carbonate?
 
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would it be 2.316 g
 
Na2CO3 + 2HCl -----------> 2NaCl + H2O

Formula weight for sodium carbonate is 105.999 grams per mole
Formula weight for hydrogen chloride is --- will not be needed
 
Zoey Brown said:
would it be 2.316 g

Don't guess - calculate.
 

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