1. The problem statement, all variables and given/known data given that 40.14g sample of hydrated NiSO4 is reduced in mass to 22.14g upon heating. Show that the formula of the hydrate is NiSO4.7H20 2. Relevant equations n / M 3. The attempt at a solution 22.14g/ 40.14g = 0.5516 (mol of NiSO4) 40.14g - 22.14 = (18 g H20 lost in heating) 18.0 / 18.02 = 0.9989 (mol of H20) ∴ mole ratio = 0.5516 : 0.9989 but this does not give the result in the ratios of 1:7 (NiSO4.7H20) stoichiometry (or chem for that matter) isn't really my thing and I have about 10 questions similar to this, can someone please point me in the right direction please?