Solving Induction Problem: Proving f0f1 + f1f2...f2n-1f2n=f2n2

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The discussion focuses on proving the equation f0f1 + f1f2 + ... + f2n-1f2n = f2n^2, where fn represents the n-th Fibonacci number. The user successfully verifies the base case for n=1 and employs mathematical induction to establish the truth of the statement for k and k+1. The key simplification involves recognizing that f(n) + f(n+1) equals f(2k+2), leading to the conclusion that the original equation holds true. The final step involves factoring to achieve the desired result.

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So i need to prove f0f1 + f1f2...f2n-1f2n=f2n2 where fn is the n-th fibonacci number..

Attempting to solve this i let n=k . Then k=1 and f22=1 which is 1=1 so that is true.

Then i show if the statement is true for k then it is true for k+1, that is f0f1 + f1f2+f2k-1f2k+f2kf2k+1+f2k+1f2k+2= f2k+22 .
I then simplify
f0f1 + f1f2+f2k-1f2k+f2kf2k+1+f2k+1f2k+2
= f2k2+ f2kf2k+1+f2k+1f2k+2.

Now I'm stuck..How do i simplify this to f2k+22 ?

Thanks
 
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What is f(n) + f(n+1)?
 
ah, its f(2k+2). Thanks I got it now. Just factor out the f(2k) then factor out the f(2k+2) and you end up with f(2k+2)f(2k+2)

Thanks!
 

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