Solving Kinematics Problem: Two Stones Dropped from 60m Cliff

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SUMMARY

The kinematics problem involves two stones dropped from a 60-meter cliff, with the second stone released 1.6 seconds after the first. When the separation between the two stones reaches 36 meters, the second stone is found to be 10.9 meters below the top of the cliff. This conclusion is reached through the application of kinematic equations that govern the motion of freely falling objects under gravity.

PREREQUISITES
  • Understanding of basic kinematics principles
  • Familiarity with the equations of motion for free fall
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Ability to perform algebraic calculations involving time and distance
NEXT STEPS
  • Review the equations of motion for free-falling objects
  • Practice solving kinematics problems involving multiple objects
  • Explore the concept of relative motion in physics
  • Study the effects of time delays in projectile motion scenarios
USEFUL FOR

Students preparing for physics quizzes, educators teaching kinematics, and anyone interested in understanding the principles of motion under gravity.

superstorebug
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I'm fairly new with this so I hope I've posted at the right place!


I don't understand how to go about doing the following kinematics problem:

Two stones are dropped from the edge of a 60-m cliff, the second stone 1.6s after the first. How far below the top of the cliff is the second stone when the separation between the two stones is 36 m?

I hope you can help because I have a quiz on this stuff tomorrow! Thanks in advance.

ANy help will be greatly appreciated.
 
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Oh the answer is 10.9 meters
 
Welcome to physics forums

Good job finding the answer. Next time please check andpost in the right section though >.>

get well rested for that quiz
 

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