MHB Solving Limit at Infinity Problem: x^(2/3) / (log^2(x))

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The discussion focuses on solving the limit problem lim x -> infinity (x^(2/3) / (x/log^2(x))). The original poster is struggling with applying L'Hopital's Rule and seeks guidance on how to simplify the expression. Another participant suggests rewriting the limit as lim x -> infinity (log^2(x) / x^(1/3)) and recommends using L'Hopital's Rule. The conversation also touches on the application of exponent laws for fractional exponents. Overall, the thread emphasizes the need for clarification on limit techniques and simplifications involving fractional exponents.
DanSlevin
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Hello, I am working on some limit problems and ran into one in which I am lost on how to proceed with:

The problem is:

lim
x -> infinity

x^(2/3)
x/(log^2(x))

I have a basic understanding of L'Hopital's Rule and attempted to apply it, but just ended up with a confusing mess. I'm assuming I'm supposed to simply first, but am not sure how to proceed. Any guidance as to the techniques to use here would be great. Thanks.
 
Last edited:
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Hard to read, I don't get very well what you mean.

This could be useful: http://www.mathhelpboards.com/forumdisplay.php?26-LaTeX-Help
 
DanSlevin said:
Hello, I am working on some limit problems and ran into one in which I am lost on how to proceed with:

The problem is:

lim
x -> infinity

x^(2/3)
x/(log^2(x))

I have a basic understanding of L'Hopital's Rule and attempted to apply it, but just ended up with a confusing mess. I'm assuming I'm supposed to simply first, but am not sure how to proceed. Any guidance as to the techniques to use here would be great. Thanks.

Is it this?

\[ \displaystyle \lim_{x \to \infty}\frac{x^{\frac{2}{3}}}{\frac{x}{(\log{x})^2}} \]
 
I'm sorry about that. I'm also having some trouble understanding the Latex syntax so hopefully this makes it a little clearer.

x2/3
________
x/log2(x)

as x approaches infinity.
 
DanSlevin said:
I'm sorry about that. I'm also having some trouble understanding the Latex syntax so hopefully this makes it a little clearer.

x2/3
________
x/log2(x)

as x approaches infinity.
$$\Large \lim_{x \to \infty}\frac{x^{\frac{2}{3}}}{\frac{x}{(\log{x})^2 }}$$

$$\Large \lim_{x \to \infty}\frac{(\log{x})^2 }{x^{\frac{1}{3}}}$$Now, try to use l'Hôpital's rule.
 
Last edited by a moderator:
Thank you for your reply and answer. Do you happen to have any sites I could look at that include examples of simplifications of this manner? I'm unfortunately unable to find any that show examples with fractional exponents and I'm a little confused as to some of the steps. Thanks again.
 
DanSlevin said:
Thank you for your reply and answer. Do you happen to have any sites I could look at that include examples of simplifications of this manner? I'm unfortunately unable to find any that show examples with fractional exponents and I'm a little confused as to some of the steps. Thanks again.

The usual laws of exponents apply for all exponents be they integer, common fractions or decimals.

CB
 

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