MHB Solving Limit Problem: $x \to 0^{-}$ e^$\frac{1}{x}$

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The limit problem discussed involves evaluating the expression $\lim_{x\to0^{-}}e^{\frac{1}{x}}$. As $x$ approaches 0 from the left, $\frac{1}{x}$ approaches $-\infty$, leading to the conclusion that $L = e^{-\infty} = 0$. This demonstrates the application of limit continuity properties, specifically $\lim_{{x}\to{a}}f(g(x))=f(\lim_{{x}\to{a}}g(x))$. The discussion also touches on the editing limitations of forum posts, noting a 2-hour cap for the first post and a 24-hour limit for subsequent posts.

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$\d{x}{{0}^{-}} e ^ {\frac{1}{x}}$

I am trying to solve this limit.

Now, if we have $\lim{x}\to{0^{-}}1/x$ , doesn't it become $\infty$?
 
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Are you trying to find the following limit?

$$L=\lim_{x\to0^{-}}e^{\frac{1}{x}}$$

If so, then you should note that:

$$\lim_{x\to0^{-}}\frac{1}{x}=-\infty$$

So, what does this tell you about $L$?
 
hey there. (Wave)
perhaps you remember that $\lim_{{x}\to{a}}f(g(x))=f(\lim_{{x}\to{a}}g(x))$ this is the limit continuity property.

so start of with $\lim_{{x}\to{0^-}}\frac{1}{x}$ this goes to $-\infty$ (you can show intermediate steps if necessary)

what is $e^{-\infty}$? once you determine that, you have your answer :o
 
Can't figure out how to edit my post to fix it. It's not under thread tools
 
At the bottom next to "Reply with quote" it should say edit post. if not, there is a time cap to edit posts i believe so it's possible you may no longer be able to edit it.
 
There is a 2 hour limit on editing the first post of a thread (which has now expired in this thread), and all other posts have a 24 hour limit.

You can just quote your first post, and then remove the quote tags and fix what you want to fix. :D
 
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