Solving ln(x+4)=2 without going in circles

[member38644]

when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2
e^2=(x+4)
ln e^2=ln(x+4)
2=ln(x+4)

and round and round i go... where do i start to go wrong?

 

[Edgardo]

Welcome to physicsforums fieldlandman,

you actually went the right way till the second line:

when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2
e^2=(x+4)

Continue there with solving FOR x!

 

[member38644]

thanks!

that was it! thanks!