Solving Math Problem: Why is m=2, not 1?

  • Thread starter Thread starter hidemi
  • Start date Start date
Click For Summary
The discussion centers on the confusion regarding the value of m in a math problem involving wave interference. The original calculation using m=1 yields incorrect results, while substituting m=2 leads to a correct answer of θ=29. However, further clarification reveals that the correct application of the formula with m=2 actually results in θ=0.57º, indicating an arithmetic error in the calculations. Additionally, the correct distance d should be 0.3*10^-9 m instead of 3*10^-9 m. The participant acknowledges the mistake and seeks further assistance.
hidemi
Messages
206
Reaction score
36
Homework Statement
An x-ray beam of wavelength 3 x~ 10^−11 m is incident on a calcite crystal of lattice spacing 0.3 nm. The smallest angle between crystal planes and the x-ray beam which will result in constructive interference is:

A. 2.9◦
B. 5.7◦
C. 12◦
D. 23◦
E. none of these

The answer is A



2 d sinθ = m λ

2x0.3x10^-9 sinθ = 2.3 x 10^-11

However, why is the m=2 ?
Relevant Equations
2 d sinθ = m λ
I calculate by :
2 *3*10^−9* sinθ = 1 * 3 *10^−11
but can not get a correct answer.

If I substitute the m by 2:
2 *3 *10^−9 * sinθ = 2* 3 * 10^−11
then the answer : θ=29 is correct

I wonder why the m is 2 not 1. Could someone help me?
 
Physics news on Phys.org
hidemi said:
I calculate by :
2 *3*10^−9* sinθ = 1 * 3 *10^−11
but can not get a correct answer.

If I substitute the m by 2:
2 *3 *10^−9 * sinθ = 2* 3 * 10^−11
then the answer : θ=29 is correct

I wonder why the m is 2 not 1. Could someone help me?
You have used d = 3*10^-9m instead of d = 0.3*10^-9 m.

And (when using m=2) your equation "2 *3 *10^−9 * sinθ = 2* 3 * 10^−11" gives θ = 0.57º, not "θ=29". So you are making some arithmetic error as well (incorrect use of brackets on calculator?).

With m=1:
mλ/(2d) = 1 * 3*10⁻¹¹ / (2 * 0.3*10⁻⁹) = 0.05
θ = sin⁻¹(mλ/(2d)) = sin⁻¹(0.05) = 2.9º (Answer A).
 
Steve4Physics said:
You have used d = 3*10^-9m instead of d = 0.3*10^-9 m.

And (when using m=2) your equation "2 *3 *10^−9 * sinθ = 2* 3 * 10^−11" gives θ = 0.57º, not "θ=29". So you are making some arithmetic error as well (incorrect use of brackets on calculator?).

With m=1:
mλ/(2d) = 1 * 3*10⁻¹¹ / (2 * 0.3*10⁻⁹) = 0.05
θ = sin⁻¹(mλ/(2d)) = sin⁻¹(0.05) = 2.9º (Answer A).
Thanks for pointing out my mistake.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

Similar threads

Replies
5
Views
731
Replies
4
Views
1K
  • · Replies 9 ·
Replies
9
Views
364
  • · Replies 6 ·
Replies
6
Views
927
  • · Replies 1 ·
Replies
1
Views
944
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
892
Replies
12
Views
2K