Solving Minimizing Arc Length: Euler-Lagrange Equations

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To minimize the arc length of the curve on the surface z=x^(3/2) connecting points (0,0,0) and (1,1,1), the integral for arc length is set up as sqrt(dx^2 + dy^2 + dz^2). The functional derived is sqrt(1 + (dy/dx)^2 + 9x/4). The Euler-Lagrange equation can be applied by taking derivatives of this functional. The initial conditions are applied by using the boundary conditions y(0) = 0 and y(1) = 1 to find the constants of integration. This approach is confirmed as being on the right track for solving the problem.
don_anon25
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The problem I am working on asks me to find the curve on the surface z=x^(3/2) which minimizes arc length and connects the points (0,0,0) and (1,1,1).
Here's what I did:
Integral [sqrt(dx^2+dy^2+dz^2)]
Integral [dx sqrt (1+(dy/dx)^2 +(dz/dx)^2]
Integral [dx sqrt (1 + (dy/dx)^2 + 9x/4)] since dz = 3/2 x^(1/2) dx

Thus the "functional" is sqrt (1 + (dy/dx)^2 + 9x/4).

Can I now take derivatives and substitute directly into the Euler-Lagrange equation and solve for y? Where/how do I apply the initial conditions -- that the endpoints are (0,0,0) and (1,1,1)?

Am I on the right track with this one?
 
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Looks like you're doing ok to me. In this case the constants of integration are obtained from the boundary conditions i.e. y(0) = z(0) = 0 and y(1) = z(1) = 1.
 

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