Solving Minimizing Arc Length: Euler-Lagrange Equations

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SUMMARY

The discussion focuses on minimizing arc length for a curve on the surface defined by the equation z=x^(3/2), connecting the points (0,0,0) and (1,1,1). The integral for arc length is established as Integral [dx sqrt (1 + (dy/dx)^2 + 9x/4)], derived from the expression for dz. The Euler-Lagrange equation is applicable for finding the optimal curve, with boundary conditions y(0) = z(0) = 0 and y(1) = z(1) = 1 being crucial for solving the problem. The participants confirm that the approach taken is correct and emphasize the importance of applying these boundary conditions.

PREREQUISITES
  • Understanding of calculus, specifically integration and differentiation.
  • Familiarity with the Euler-Lagrange equation in the context of calculus of variations.
  • Knowledge of parametric equations and their applications in geometry.
  • Basic concepts of boundary value problems in differential equations.
NEXT STEPS
  • Study the derivation and application of the Euler-Lagrange equation in various optimization problems.
  • Explore examples of minimizing arc length using calculus of variations.
  • Learn about boundary value problems and their significance in differential equations.
  • Investigate the implications of boundary conditions in solving differential equations.
USEFUL FOR

Mathematicians, physics students, and engineers interested in optimization problems, particularly those involving calculus of variations and boundary value problems.

don_anon25
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The problem I am working on asks me to find the curve on the surface z=x^(3/2) which minimizes arc length and connects the points (0,0,0) and (1,1,1).
Here's what I did:
Integral [sqrt(dx^2+dy^2+dz^2)]
Integral [dx sqrt (1+(dy/dx)^2 +(dz/dx)^2]
Integral [dx sqrt (1 + (dy/dx)^2 + 9x/4)] since dz = 3/2 x^(1/2) dx

Thus the "functional" is sqrt (1 + (dy/dx)^2 + 9x/4).

Can I now take derivatives and substitute directly into the Euler-Lagrange equation and solve for y? Where/how do I apply the initial conditions -- that the endpoints are (0,0,0) and (1,1,1)?

Am I on the right track with this one?
 
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Looks like you're doing ok to me. In this case the constants of integration are obtained from the boundary conditions i.e. y(0) = z(0) = 0 and y(1) = z(1) = 1.
 

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