Solving Momentum Collision Problems

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SUMMARY

The forum discussion addresses a momentum collision problem involving two objects: a 950kg object traveling east and a 1900kg object traveling north. After the collision, both objects move together at 16m/s at an angle of 24 degrees east of north. The initial velocities were incorrectly calculated due to a misunderstanding of vector components, specifically the use of sine and cosine functions. The correct approach requires recognizing that 24 degrees east of north indicates a greater northward component than eastward.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with vector decomposition in physics
  • Knowledge of trigonometric functions (sine and cosine)
  • Ability to solve equations involving mass and velocity
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  • Study the principles of momentum conservation in two-dimensional collisions
  • Learn about vector decomposition and how to resolve vectors into components
  • Review trigonometric identities and their applications in physics problems
  • Practice solving collision problems using real-world examples
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This discussion is beneficial for physics students, educators, and anyone involved in solving collision problems in mechanics, particularly those focusing on momentum and vector analysis.

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[SOLVED] Momentum - collision

Homework Statement



An object of mass 950kg traveling east collides with an object of mass 1900kg traveling north. The two objects then move off together at 16m/s in a direction of 24degrees east of north. Find their respective velocities prior to the collision.

Homework Equations



p = mv

The Attempt at a Solution


Momentum after collision = 2850 x 16 = 45600
As momentum is a vector, then breaking it into its components we get:
Object 1: 950 x v1 = (45600)cos24 ... v1=43.85m/s
Object 2: 1900 x v2 = (45600)sin 24... v2=9.76m/s

I thought this seemed simple enough, but apparently the answers are wrong... can anyone see where I might have made mistake, or am I just going about it the wrong way altogether?
 
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Ginerva123 said:

Homework Statement



An object of mass 950kg traveling east collides with an object of mass 1900kg traveling north. The two objects then move off together at 16m/s in a direction of 24degrees east of north. Find their respective velocities prior to the collision.

Homework Equations



p = mv

The Attempt at a Solution


Momentum after collision = 2850 x 16 = 45600
As momentum is a vector, then breaking it into its components we get:
Object 1: 950 x v1 = (45600)cos24 ... v1=43.85m/s
Object 2: 1900 x v2 = (45600)sin 24... v2=9.76m/s

I thought this seemed simple enough, but apparently the answers are wrong... can anyone see where I might have made mistake, or am I just going about it the wrong way altogether?

you got the sin/cos mixed up... 24 degrees "east of north" is pointing more north than east...
 

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