- #1

Lori

## Homework Statement

A 1000 kg car approaches an intersection traveling north at 20.0 m/s . A 1200 kg approaches this same intersection traveling east at 22.0 m/s. The two car collides and lock together. Ignoring any external forces , what is the velocity of the car immediately after the collision.

a)29.7 m/s, 47.7 degrees east of north

b)21.1, 47.7 west of south

c)15.1 m/s, 52.8 east of north

d) 21.1 m/s , 52.8 east of north

e) 21.1 m/s 47.7 east of north

## Homework Equations

P = mv (momentum)

Mass 1 car = 1000

mass 2 car = 1200

## The Attempt at a Solution

This is a inelastic collision so the velocity final would be the same for the two objects with mass 1 + mass 2

First thing i would do would be to find Py (momentum in y direction) and Px (in x direction). If i find the magnitude by squaring them and tying the sqrt, I would be magnitude of momentum total. Thus, if i solve for v in P = mv, where m is the total mass, i can get v. The Py and Px will also give me the direction right?

My work:

Py = 1000kg*20 = 20000

Px = 1200kg*22 m/s = 26400

P = 33120.37 = mv

33129.37 = (1000+1200kg)v

v = 15.1 m/s and the direction is east of north (north west)