Solving ODE with Frobenius Form Solution

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SUMMARY

This discussion focuses on solving an ordinary differential equation (ODE) using a Frobenius form solution. The recurrence relation derived is a(k) = -2/(2k-1) a(k-1), and the user seeks to express this in terms of a(0). The user notes the presence of a (2n-1)! term in the denominator and a (-2)^(n) term in the numerator, indicating the structure of the general solution. The conversation emphasizes the need for simplification to establish a general expression for the solution.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with recurrence relations
  • Knowledge of the Frobenius method for solving differential equations
  • Basic combinatorial mathematics, specifically factorial notation
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  • Research the Frobenius method for solving ODEs
  • Study recurrence relations and their general forms
  • Learn about factorials and their applications in series solutions
  • Explore techniques for simplifying expressions involving recurrence relations
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Mathematicians, students studying differential equations, and anyone interested in advanced methods for solving ODEs using series solutions.

Juggler123
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I'm finding a solution to and ODE using a Frobenius form solution, I have worked through the question and have ended up with a recurrence of the form;

a(k) = -2/(2k-1) a(k-1)

I'm trying to find a general reccurence in terms of a(0) but am finding it a bit difficult, I know it has to have a (2n-1)! term on the bottom of the fraction and a (-2)^(n) term on top but I'm a bit stuck as to where to go after this.

Sorry I haven't Latex-ed anything, I don't know how!

Any help would be fantastic, thanks.
 
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good luck finding anyone who wants to actually write out frobenius method. If i remember correctly, there may be a point before the end where a(0) is established. and it could very well be 0. so heads up for that. otherwise, re-do it.
 
I'm not looking for anyone to write out Frobenius method for me, I just need some help in simplifying the expression in terms of a(0), so that I can get a general expression for a solution. The problem doesn't have anything to do with Frobenius method at all.
 

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