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Frobenius method for fourth order linear ODE

  1. Dec 18, 2013 #1
    By using frobenius method I find the roots of the indicial equation of a 4th order ODE to be
    0, 1, 1, 2
    Now, what is the form of the corresponding series solution of this equation with log terms?
     
  2. jcsd
  3. Dec 19, 2013 #2

    HallsofIvy

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    You should be looking for a solution to the form
    [tex]\sum a_nx^n+ \sum b_nx^{n-1}+ log(x)\sum c_n x^{n-1}+ \sum d_n x^{n-2}[/tex]
     
  4. Dec 19, 2013 #3
    no matter about the condition that the roots differ by integers?
     
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