Solving Oil Drop Experiment: Calculate Largest e Value

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cake_is_a_lie
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Homework Statement


The values for the charges on oil drops are 3,99 6,65 2,66 10,64 3,99 and 9,31
all these multiplied with x10-19C.
What is the largest value of the fundamental unit of charge that is consistent with the measured charges?


Homework Equations


Fundamental unit of charge is e=1,60x10-19C


The Attempt at a Solution


The question confuses me a little bit. Taking mean average is useless because the highest value is asked. I don't find also any reason to calculate ratios between the measured values althought 6,65/3,99=1,6666...
Any ideas?
 
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hi cake_is_a_lie! :smile:
cake_is_a_lie said:
The values for the charges on oil drops are 3,99 6,65 2,66 10,64 3,99 and 9,31 …

well, they're (approximately) 12/3, 20/3, 8/3, 32/3, and 28/3 … :wink:
 
Thank you for answering.
But I don't really understand the point. Actually this time the explanation and deduction is more useful than the actual answer.
 
tiny-tim said:
well, what's the largest unit consistent with 12/3, 20/3, 8/3, 32/3, and 28/3, being multiples of that unit? :smile:
cake_is_a_lie said:
If I understand right it is 3. What I meant before was that how did you deduced these common fraction.

nooo :redface: … each value has to be a multiple of the unit

how can 20/3 be a multiple of 3?

you need to find the highest common factor (the highest number which goes into each value a whole number of times) :smile: