Solving Partial Derivatives Homework: fx(x,y) and fy(x,y)

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SUMMARY

The discussion focuses on calculating the partial derivatives fx(x,y) and fy(x,y) for the function f(x,y) = x/(x + y²) using the limit definition. The initial attempt incorrectly suggests that fx(x,y) equals 1, but further analysis reveals that the correct limit is y²/(x + y²)². Participants emphasize the importance of algebraic manipulation to simplify expressions before applying limits to avoid erroneous results.

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Students studying calculus, particularly those focusing on multivariable functions and partial derivatives, as well as educators looking for examples of common pitfalls in limit calculations.

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Homework Statement



Use the definition of partial deriviatives as limits to find fx(x,y) and fy(x,y).


Homework Equations



f(x,y) = [tex]\frac{x}{x + y^{2}}[/tex]


The Attempt at a Solution



I don't think this is right because I think I should have an answer of 1.

fx(x,y) = lim h-> 0 [f(x+h,y) - f(x,y)]/h

=lim h->0 [(x+h)/(x+h+y^2) - x/(x+y^2)]/h
=lim h->0 [(x+h)/(x+h+y^2) - x/(x+y^2)]*1/h
=lim h->0 (x+h)/(xh+h^2+(y^2)h) - x/(xh+(y^2)h)
=lim h->0 ((x/h)+1)/(x+h+y^2) - (x/h)/(x+y^2)
=1/(x+y^2)
 
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I don't think the answer is 1. Look at your last line. You got things like (x/h). If you take lim h->0, that goes to infinity. You need to do enough algebra to cancel the h in the denominator before you can find a sensible limit. Combine (x+h)/(x+h+y^2) - x/(x+y^2) into single fraction and simplify the numerator before you take the limit.
 
fx(x, y) is not equal to 1.

I think you have an error in this line:
=lim h->0 ((x/h)+1)/(x+h+y^2) - (x/h)/(x+y^2)

I don't understand how you got to this expression from the one just before it.

After taking the limit, you should end up with y^2/(x + y^2)^2
 

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