Solving ytzz=yzzzz+delta(t) with given initial and boundary conditions

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jimmygriffey
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Hi:

I have the following PDE:

ytzz=yzzzz+delta(t)

With I.C.: t=0, y=0; and B.C.s: z=0, y=0,yzz=0; z=-x,y=0,yz=0

Can someone show me how to solve it?

Kevin
 

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Yes, it is δ(t). The one is very similar to the previous one. After taking Laplace transform in t, this one will become the previous one. If I use the method pointed by other people, I have hard time to convert back (inverse Laplace transform) to time domain. That's why I ask the question again.

Kevin
 
jimmygriffey said:
Yes, it is δ(t). The one is very similar to the previous one. After taking Laplace transform in t, this one will become the previous one. If I use the method pointed by other people, I have hard time to convert back (inverse Laplace transform) to time domain. That's why I ask the question again.

Kevin
Yes - if one uses the Laplace Transform (which takes an equation from time domain to frequncy domain) then I believe it is the same problem. I'm expecting the problem is separable, i.e. Y(z,t) = Z(z)T(t). See if that works.