Solving Probability Problem: Red Cube 6 & Sum of Cubes 10

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SUMMARY

The probability problem involves rolling two number cubes, one red and one white, to determine the likelihood that the red cube shows a 6 and the total sum of both cubes equals 10. The correct calculation is that the probability of the red cube being a 6 is 1/6, and the only combination that results in a total of 10 is when the white cube shows a 4. Therefore, the overall probability is 1/6 multiplied by 1/6, resulting in a final probability of 1/36. The initial misunderstanding arose from misinterpreting the conditions of the problem.

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MACHO-WIMP
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The question is:
Two number cubes are rolled--one is red and the other is white. Find the probability that the red cube is a 6 and the sum of the two cubes is 10.

I said that it is 1/6 for being a 6 and since only a 4 can add up to 10 its 1/6*1/6=1/36. But my teacher said it was wrong. Please help!
 
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I must say that I think you are correct and your teacher wrong. Are you sure you two are talking about the same problem? If the problem were just "one cube is 6 and the two sum to 10" then then you could get a 6 on either, and a four on the other: (1/6)(1/6)+ (1/6)(1/6)= 1/18.
 
MACHO-WIMP said:
The question is:
Two number cubes are rolled--one is red and the other is white. Find the probability that the red cube is a 6 and the sum of the two cubes is 10.

I said that it is 1/6 for being a 6 and since only a 4 can add up to 10 its 1/6*1/6=1/36. But my teacher said it was wrong. Please help!

You are correct; your teacher made a mistake. Your teacher would be correct IF you were not told the color of the "6" die---but you *were* told its color.

RGV
 

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